Bonsoir
Quelle expression ne se factorise pas en 2(n + 1) :
3n(n + 1) - (3n - 2)(n + 1)
= (n + 1)[3n - (3n - 2)]
= (n + 1)(3n - 3n + 2)
= (n + 1) x 2
= 2(n + 1) => se factorise
4n + 4 - 2n - 2
= 2n + 2
= 2 * n + 2 * 1
= 2(n + 1) => se factorise
(10n + 10)/5
= 10n/5 + 10/5
= (5 x 2n)/5 + (5 x 2)/5
= 2n + 2
= 2(n + 1) => se factorise
[5(n + 1)]/2 - (n + 1)/2
= (5n + 5 - n - 1)/2
= (4n + 4)/2
= 4(n + 1)/2
= 2(n + 1) => se factorise
6(n - 1) - 4(n - 2)
= 6n - 6 - 4n + 8
= 2n + 2
= 2(n + 1) => se factorise
3(n + 1) - n + 1
= 3n + 3 - n + 1
= 2n + 4
= 2(n + 2) => ne se factorise pas
2(n - 1) + 4
= 2n - 2 + 4
= 2n + 2
= 2(n + 1) => se factorise
3(n + 3) - n - 7
= 3n + 9 - n - 7
= 2n + 2
= 2(n + 1) => se factorise
