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Sagot :

1. Df= [0; 6] car M est un point de [AB]


2.a. Aire(BEM)=( BM× BE)/2 = (x×2)/2 =x


b. Aire(BCDM)= (B+b)/2 × h = (6+x)/2 ×2 =6+x
(On a B= CD =6, b= BM=x, h= BC=2)


c. f(x)= x+ 6+x = 2x+6


3.a. f(x)= 10 equivaut à 2x+6=10
Donc 2x=10-6=4 d'où x=2

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