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Sagot :

Bonjour,

1) f(x) = -x²-2x+8

2) -(x-2)(x+4) = -(x²+4x-2x-8) = -x²-4x+2x+8 = -x²-2x+8 = f(x)

    -(x+1)²+9 = -(x²+2x+1)+9 = -x²-2x-1+9 = -x²-2x+8 = f(x)

3) f(2) = -2²-2(-2)+8 = -4+4+8 = 8

   f(x)=0 ⇒ -(x-2)(x+4) = 0

             ⇒  x-2=0  ou  x+4=0

             ⇒   x = 2  ou  x = -4

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