Answered

Bonjour c est pour factoriser ça

[2*(5x-2)]AU CARRÉ -(10x-4)

Pour à la fin trouver

(5x-2)(20x-10)

Merci beaucoup

Sagot :

MARGESIMPSON1

Bonjour

= [2(5x-2)]²-(10x-4)

= (2(5x-2))²-(10x-4)

= (2(5x-2))²-10x+4

= (10x-4)²-10x+4

= 100x²-80x+16-10x+4

= 100x²-90x+16+4

= 100x²-90x+20

= 10(10x²-9x+2)

= 10(10x²-4x-5x+2)

= 10(2x(5x-2)-5x+2)

= 10(2x(5x-2)-(5x-2))

= (5x-2)(20x-10)

Bonne journée.