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équations produits nuls

(2x+7)(3x-12)=0

x = - 7/2 ou 123 = 4

b. (5y-2)(6y+9)=0

y =  2/5 ou - 9/6 = - 3 /2

napsazz13

Réponse:

bonjour

a. (2x+7)(3x-12) = 0

2x+7 = 0 3x-12 = 0

2x = -7 3x = 12

x = -7/2 x = 12/3 = 4

b. (5y-2)(6y+9) = 0

5y-2 = 0 6y+9 = 0

5y = 2 6y = -9

y = 2/5 y = -9/6 = -1,5