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Sagot :

MARGESIMPSON1

Bonsoir,

• (x+1)²+(x+1)(2x+3) = 0

• (x+1)(x+1+2x+3) = 0

• (x+1)(3x+1+3) = 0

• (x+1)(3x+4) = 0

• x+1 = 0 ; 3x+4 = 0

• x = -1 ; 3x+4 = 0

• x = -1 ; x = -4/3

↳ Équation à 2 solutions : x1 = -1 ; x2 = -4/3

/ = fraction.

Bonne soirée.

Bonsoir !

Factoriser :

(x+1)²+(x+1)(2x+3) = 0

(x+1)(x+1)+(x+1)(2x+3) = 0

(x+1)(x+1)+(2x+3) = 0

(x+1)(x+1+2x+3) = 0

(x+1)(3x+4) = 0

(x+1) = 0 => x = -1

(3x+4) = 0 => x = -4/3

Bon courage.

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