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Bonjour j’ai besoins d’aide pour cet exercice, je dois résoudre les équations suivante

1/ (2x -3)^2 =81

2/ (2x-4) (x-1) -(x-1) (-x-5) = 0

3/ (7x - 8)^2 - (5x -9)^2 =0

Sagot :

Bsr

1) (2x-3)² = 81

1) 2x-3 = ±9

1) 2x-3 = -9 ; 2x-3 = 9

1) x = -3 ; 2x-3 = 9

1) x = -3 ; x = 6

Équation à 2 solutions x1 = 6 ; x2 = -3

2)(2x-4)(x-1)-(x-1)(-x-5) = 0

2) (x-1)(2x-4-(-x-5)) = 0

2) (x-1)(2x-4+x+5) = 0

2) (x-1)(3x-4+5) = 0

2) (x-1)(3x+1) = 0

2) x-1 = 0 ; 3x+1 = 0

2) x = 1 ; 3x+1 = 0

2) x = 1 ; x = -1/3

Équation à 2 solutions → x1 = -1/3 ; x2 = 1

3) (7x-8)²-(5x-9)² = 0

3) (7x-8-(5x-9))(7x-8+(5x-9)) = 0

3) (7x-8-5x+9)(7x-8+(5x-9)) = 0

3) (7x-8-5x+9)(7x-8+5x-9) = 0

3) (2x-8+9)(7x-8+5x-9) = 0

3) (2x+1)(7x-8+5x-9) = 0

3) (2x+1)(12x-8-9) = 0

3) (2x+1)(12x-17) = 0

3) 2x+1 = 0 ; 12x-17 = 0

3) x = -1/2 ; 12x-17 = 0

3) x = -1/2 ; x = 17/12

Équation a 2 solutions → x1 = 17/12 ; x2 = -1/2

Voilà !

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