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Sagot :

Bonjour,

4) f(x) ≤ g(x) pour x ∈ [0;2]

et f(x) > g(x) pour x ∈ ]-∞;0[ ∪ ]2;+∞[

5) f o g(x) =

f[g(x)] = (1/8) . [2x/(x + 2)]³ = (1/8) . 8x³/(x + 2)³ = x³/(x + 2)³

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