Sagot :
bjr
f(x) = - 8x + 1
donc
f(5) = - 8*5 + 1 = - 39
f(x) = x² + 4x
donc
f(5) = 5² + 4*5 = 45
et fonction cube => f(x) = x³
donc f(5) = ... vous avez compris
bonjour
h (x) = - 8 x+ 1
h ( 5 ) = - 8 *5 + 1 = - 39
f (x) = x² + 4 x
f ( 5) = 5 ² + 5*4 = 25 + 20 = 45
g (x ) = x ³