Bonjour,
2) p(E ∩ L) = 96% x 95% = 91,2%
3) p(L) = P( E ∩ L ) + p(Ebarre ∩ L)
= 91,2% + 4% x 90% = 91,2% + 3,6% = 94,8%
4) pLbarre(Ebarre) (proba de Ebarre sachant Lbarre)
= p(Lbarre ∩ Ebarre)/p(Lbarre) (intersection/condition)
= (4% x 10%)/(100% - 94,8%) (p(Lbarre) = 100% - p(L))
≈ 7,69%
