FABRICE26
Answered

On sait que x⩾0. Comparer 1/(x+7) et 1/(x+2).

On sait que x⩽0. Comparer 1/(x–6) et 1/(x–10).

On sait que x⩾3. Comparer 1/(4x–2) et 1/10.

Sagot :

WASSIMHIDAKHALOUFI

Réponse:

1/(x+7)>1/(x+2)

1/(x+6)>1/(x-10)

1/(4x-2)>1/(x-10)