Sagot :
bonsoir
f(x) = (2x - 3)(x + 1) - 4(x+1)
f (x) = 2 x² + 2 x - 3 x - 3 - 4 x - 4
f (x) = 2 x² - 5 x - 7
f (x) = ( x + 1 ) ( 2 x - 3 - 4 )
f (x) = ( x + 1 ) ( 2 x - 7 )
( x + 1 ) ( 2 x - 7 ) = 0
x = - 1 ou 7/2
bonsoir
f(x) = (2x - 3)(x + 1) - 4(x+1)
f (x) = 2 x² + 2 x - 3 x - 3 - 4 x - 4
f (x) = 2 x² - 5 x - 7
f (x) = ( x + 1 ) ( 2 x - 3 - 4 )
f (x) = ( x + 1 ) ( 2 x - 7 )
( x + 1 ) ( 2 x - 7 ) = 0
x = - 1 ou 7/2