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Sagot :

HIPOUCHE2011

Réponse:

EF(2_1,_1+3,1_4)=(1,2,-3)

EG(-1_1,0+3,2_4)=(-2,3,-2)

-3EG(_3×(-2),-3×3,-3×(-2))=(6,-9,6)

2EF=(2,4,-6)

-3EG+2EF=(8,-5,0)

FG=(-1_2,0+1,2_1)=(-3,1,1)

2FG=(-6,2,2)

2FG+EF=(-5,4,-1)

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