Réponse:
Let's first see the reaction
H2SO4+2NaOH→Na2SO4+2H2OH2SO4+2NaOH→Na2SO4+2H2O
From the above-mentioned reaction, we come to know that 11 mole of H2SO4H2SO4 is required to neutralize 22 moles of NaOHNaOH.
Let's find out no. of moles of NaOHNaOH present in 8g ofNaOHNaOH. Molar mass of NaOHNaOH is approximately equal to 40gmol−140gmol−1. Therefore, no. of moles of NaOH
==840=210=0.2840=210=0.2
Let no. of moles of H2SO4H2SO4 required to neutralize 0.2 moles ofNaOHNaOH be xx
∴∴ 1x∴xx=2