Bonjour
Résoudre ces équations :
(x-3) (2x+4)=0
x - 3 = 0 ou 2x + 4 = 0
x = 3 2x = - 4
x = - 4/2 = - 2
(5x-4) (-3x+7)=0
5x - 4 = 0 ou - 3x + 7 = 0
5x = 4 - 3x = - 7
x = 4/5 x = 7/3
(6x+4) (2x-1)=0
6x + 4 = 0 ou 2x - 1 = 0
6x = - 4 2x = 2
x = - 4/6 = - 2/3 x = 2/2 = 1
(3/4x+5/3) x=0
3/4x + 5/3 = 0 ou x = 0
3/4x = - 5/3
9x = - 20
x = - 20/9
3x(x-3)au carre =0
3x = 0 ou x - 3 = 0
x = 0 x = 3.