bjr
n le premier
m le second
on aura donc comme suite
n m n+m n+m +m n+m+m + n+m n+m+m+n+m + n+m+m
n m n+m n+2m 2n+3m 3n+5m
3 7 10 17 27 44
3 7 3+7 10 +7 17 + 10 27 + 17
5eme nbre = n+m+m+n+m = 2n+3m
et x 4 = 4 x (2n+ 3m) = 8n + 12m
somme des 6 nbres = n + m + (n+m) + (n+2m) + (2n+3m) + (3n+5m)
= n+n+n+2n+3n + m+m+2m+3m+5m
= 8n + 12m
donc vrai :)
