Réponse:
a)
[tex]f(5) = 5 ^{3} - 3 \times 5 {}^{2} + 5 + 1 \\ = 125 - 75 + 6 \\ = 56[/tex]
b)
[tex]f(1) = 1 ^{3} - 3 \times 1 {}^{2} + 1 + 1 \\ = 1 - 3 + 2 \\ = 0[/tex]
c)
[tex]f( - 1) = {( - 1)}^{3} - 3 \times {( - 1)}^{2} +( - 1) + 1 \\ = - 1 - 3 \times 1 + 0 \\ = - 4[/tex]
d)
[tex]f(0) = {0}^{3} - 3 \times {0}^{2} + 0 + 1 \\ = 0 - 0 + 0 + 1 \\ = 1[/tex]
