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Bonjour pouvez-vous m'aider svp Développer et réduire les expressions suivantes
(5x+2) (2x-1) - (2x+1) (x+2)
(3x-2) (4x-1)
(y+2)²
(2x+3)²
(x-7)²
(1-y)²
(a+2) (a-2)
(a-2)²
(2a+4) (2a-4)
(3/4x-2)²
(4/3x + 1/2)²
(x+2) (x-2) - (x+3) (x-3)
(5x +2)² + (2x-1)²
(2x +2y)² + (2x - 2y)² - 3(x-y) (x+y)
Merci beaucoup

Sagot :

THUNDERINDI
Alors:

(5x+2)(2x-1)-(2x+1)(x+2) = 10x^2 -5x +4x -2 -2x^2 -4x - x -2 = 8x^2-6x -4
(3x-2)(4x-1) = 12x^2 -3x -8x +2 = 12x^2 - 11x+2
(y+2)^2 = y^2 + 2*2*y + 2^2=y^2 +4y + 4
(2x+3)^2= 4x^2+2*2x*3+ 3^2 = 4x^2 +12x +9
(x-7)^2 = x^2 -14x +49
(1-y)^2 = 1 -2y + y^2
(a+2)(a-2) = a^2 - 2^2 = a^2 - 4
(a-2)^2 = a^2 -4a +4
(2a+4)(2a-4) = (2a)^2 - 4^2 = 4a^2 - 16
(3/4x-2)^2 = 9/16x^2 - 2*6/4x + 4^2 = 9/16x^2 +13
(4/3x + 1/2)^2 = 16/9x^2 + 4/3x +1/4
(x+2)(x-2) - (x+3)( x-3) = x^2 +4 - (x^2 - 9) = 13
(5x+2)^2 + (2x-1)^2 = 25x^2 +20x + 4 +4x^2 -4x +1= 29x^2 + 16x +5
(2x+2y)^2 + (2x - 2y)^2 - 3(x-y)(x+y) = 4x^2 + 8xy + 4y^2 +4x^2 - 8xy +4y^2 -3x^2 + 3y^2= 5x^2 +11y^2

L’exercice étant long je t’invite à vérifier mes calculs ;)

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