Réponse :
Bonjour,
[tex]D = 22^6 \times \dfrac{33^3}{8 \times 6^3}\\\\= (2 \times 11)^6 \times \dfrac{(3 \times 11)^3}{8\times (2 \times 3)^3}\\\\= 2^6 \times 11^6 \times \dfrac{3^3 \times 11^3}{2^3 \times 2^3 \times 3^3}\\\\= \dfrac{2^6 \times 11^6 \times 3^3 \times 11^3}{2^3 \times 2^3 \times 3^3}\\\\= \dfrac{2^6 \times 3^3}{2^6 \times 3^3} \times 11^6 \times 11^3\\\\= 11^9[/tex]
