bonjour
f (x) = 3 x² + 5 x - 2
1 . domaine def = R
f ( -1) = 3 - 5 - 2 = - 4
f ( 0) = - 2
f ( 4) = 3 x 16 + 5 x 4 - 2 = 48 + 20 - 2 = 66
g (x) = ( 3 x - 1 ) ( x + 2 )
g (x) = 0 pour x = 1/3 et - 2
3 x² + 6 x - x - 2 = - 2
3 x² + 5 x - 2 + 2 = 0
x ( 3 x + 5 ) = 0
x = 0 ou - 5/3