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SCOLADAN

Bonjour,

1)a) Cm₁ x V₁ = Cm₃ x V₃

⇒ V₁ = V₃ x Cm₃/Cm₁ = 50 x 25,0/125 = 10,0 mL

b) pipette jaugée de 10 mL

2) Cm₄ = Cm₁ x V₁/V₄ = 125 x 10,0/100,0 = 12,5 g.L⁻¹

3) 12,5 g.L⁻¹ < Cm inconnue < 25,0 g.L⁻¹

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