Sagot :
Bonjour,
Résoudre :
1/x= 1/7
x= 7 S= { 7 }
1/x= 5/6
5x= 6
x= 6/5 S= { 6/5 }
1/x ≤-1/8 x≠ 0
1/x + 1/8 ≤ 0
(1*8+1*x)/(x*8) ≤ 0
(8+x)/ 8x ≤ 0
x= -8 S= [ -8 ; 0 [
1/x ≤ 12
1/x-12 ≤ 0
(1-12x)/x ≤ 0
x≠ 0
x= 1/12 S= ]- ∞,; 0 [ U [ 1/12; +∞ [
3/x ≤ 6 x≠ 0
3/x - 6 ≤ 0
(3-6x)/x ≤ 0
x= 3/6= 1/2
S= ] -∞; 0 [ U [ 1/2; + ∞ [