ROSENACADET82
Answered

a(m+n-b)=
5(a+b+2)=
6(a-b-c)=
4(2a-4+c)=
(4a+5-c)×2a=

appliquer la distributuvité

aidez moi svp​

Sagot :

Bonsoir,

a(m+n-b )=  am + an + ab

5(a+b+2) = 5a + 5b + 5*2 = 5a + 5b + 10

6(a-b-c) = 6a - 6b - 6c

4(2a-4+c) =4*2a + 4*(-4) + 4c = 8a + 4c - 16

(4a+5-c)×2a = 2a * 4a + 2a*5 + 2a*(-c) = 8a² + 10a - 2ac