bonjour
f (x) = 6 x ³ - 13 x² + 9 x - 2
1 ) ( 2 x - 1 ) ( 3 x² - 5 x + 2 )
= 6 x³ - 10 x² + 4 x - 3 x² + 5x - 2
= 6 x³ - 13 x² + 9 x - 2
2 ) 3 x² - 5 x + 2
Δ = ( - 5 )² - 4 ( 3 * 2 ) = 25 - 24 = 1 = 1 ²
x 1 = ( 5 - 1 ) / 6 = 4 /6 = 2/3
x 2 = ( 5 + 1 ) / 6 = 6 /6 = 1
f (x) = ( x - 2 /3 ) ( x - 1 )
f (x) = 0
x = 2/3 ou 1
