Sagot :
Réponse :
Bonjour
a) √28 = √(7×4) = √7 × √4 = 2√7
b) √50 = √(25×2) = √25 × √2 = 5√2
c) 4√27 = 4√(9×3) = 4√9×√3 = 4×3×√3 = 12√3
d) -√32 = -√(16×2) = -√16 × √2 = -4√2
bonjour
Justifier que chaque simplification est correcte.
a. √28 vaut 2√7
√28 = √(4 x 7) = √(2^2 x 7) = 2√7
b. √50 vaut 5√2
√50 = √(25 x 2) = √(5^2 x 2) = 5√2
c. 4√27 vaut 12√3
4√27 = 4√(3 x 9) = 4√(3 x 3^2) = 4 x 3√3 = 12√3
d. -√32 vaut. -4 √2
-√32 = -√(16 x 2) = -√(4^2 x 2) = -4√2