Bonjour pouvez m’aider à résoudre ces problèmes de maths de seconde


Bonjour Pouvez Maider À Résoudre Ces Problèmes De Maths De Seconde class=

Sagot :

Bonjour

Écrire les nombres suivants sous forme de fractions irréductibles :

A = 3/7 - 3

A = 3/7 - (3 x 7)/(1 x 7)

A = 3/7 - 21/7

A = -18/7

B = 1/2 - 1/3 + 1/6

B = (1 x 3)/(2 x 3) - (1 x 2)/(3 x 2) + 1/6

B = 3/6 - 2/6 + 1/6

B = 2/6

B = 2/(2 x 3)

B = 1/3

C = -3/8 : 9/4

C = -3/8 x 4/9

C = -3/9 x 4/8

C = -3/(3 x 3) x 4/(4 x 2)

C = -1/3 x 1/2

C = -1/6

D = (-1/2) x (-2/3) x (-3/4) x (-4/5)

D = (1 x 2 x 3 x 4)/(2 x 3 x 4 x 5)

D = 1/5

E = 4 x (5/6 - 6/5)

E = 4 x [(5 x 5)/(6 x 5) - (6 x 6)/(5 x 6)]

E = 4 x (25/30 - 36/30)

E = 4 x (-11/30)

E = -11 x 4/30

E = -11 x (2 x 2)/(2 x 15)

E = - 11 x 2/15

E = -22/15

F = (1/2 + 5/3) x (1/2 - 5/6)

F = [(1 x 3)/(2 x 3) + (5 x 2)/(3 x 2)] x [(1 x 3)/(2 x 3) - 5/6]

F = (3/6 + 10/6) x (3/6 - 5/6)

F = 13/6 x (-2/6)

F = 13/6 x -1/3

F = -13/18

G = (2 - 1/3)/(2 + 1/3)

G = (6/3 - 1/3) / (6/3 + 1/3)

G = 5/3) / (7/3)

G = 5/3 x 3/7

G = 3/3 x 5/7

G = 5/7

H = (2/3 - 4/7)/(11/5)

H = (14/21 - 12/21) x 5/11

H = 2/21 x 5/11

H = 10/231

I = (2/3 + 1/2)/(4/5 - 3/4)

I = (4/6 + 3/6) / (16/20 - 15/20)

I = 7/6) / (1/20)

I = 7/6 x 20

I = 7 x 20/6

I = 7 x (2 x 10)/(2 x 3)

I = 7 x 10/3

I = 70/3

J = (1/6 + 3/4 - 1)/(7/12 - 5/9 + 11/18)

J = (2/12 + 9/12 - 12/12) / (21/36 - 20/36 + 22/36)

J = -1/12) / (23/36)

J = -1/12 x 36/23

J = -36/12 x 1/23

J = -3 x 1/23

J = -3/23

K = [5 x (2 - 19/3)] / (11/6 : 5/2)

K = (5 x (6/3 - 19/3)) / (11/6 x 2/5)

K = (5 x (-13/3)) / (11/5 x 2/6)

K = (-65/3) / (11/5 x 1/3)

K = -65/3) / (11/15)

K = -65/3 x 15/11

K = -975/33

L = 1 + 1/(2 + 1/(3 + 1/4))

L = 1 + 1/(2 + 1/(12/4 + 1/4))

L = 1 + 1/(2 + 1/(13/4))

L = 1 + 1/(2 + 1 x 4/13)

L = 1 + 1/(2 + 4/13)

L = 1 + 1/(26/13 + 4/13)

L = 1 + 1/(30/13)

L = 1 + 1 x 13/30

L = 1 + 13/30

L = 30/30 + 13/30

L = 43/30