aidez moi svp mercii beaucoup

a) -2(5 x - 2) = -4
b) 3(x + 2) = 2 x - 5
c) 5x-19 = 24 x - (3 x+ 13)
d) 6+ 2(8 + 6 x) - 9(3 x+4)= 0
e) (3 x-6)-(-4x + 6) = 2 x + 8
f) (3 x - 1) + (7 - x)=0


Sagot :

[tex]a) -2(5 x - 2) = -4\\-10x+4=-4\\-10x=-8\\x=\frac{8}{10}=\frac{4}{5}[/tex]

[tex]b) 3(x + 2) = 2 x - 5\\3x+6=2x-5\\3x-2x=-5-6\\x=-11[/tex]

[tex]c) 5x-19 = 24 x - (3 x+ 13)\\5x-19 = 24 x -3 x- 13\\5x-24x+3x=-13+19\\-16x=6\\x=-\frac{6}{16} =-\frac{3}{8}[/tex]

[tex]d) 6+ 2(8 + 6 x) - 9(3 x+4)= 0\\6+16+12x-27x-36=0\\12x-27x=36-6-16\\-15x=14\\x=-\frac{14}{15}[/tex]

[tex]e) (3 x-6)-(-4x + 6) = 2 x + 8\\3x-6+4x-6=2x+8\\3x-2x+4x=12+8\\5x=20\\x=4[/tex]

[tex]f) (3 x - 1) + (7 - x)=0\\3x-1+7-x=0\\2x=-6\\x=-\frac{6}{2}=-3[/tex]