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Sagot :

NACIBA

Réponse:

[tex](\pi \times {od}^{2}) -( \pi \times {oc}^{2} ) = \pi \times ( {6}^{2} - {4}^{2} ) = \pi \times (36 - 16) = 20\pi[/tex]

[tex]o = \frac{bc}{2} \\ od = oc + cd = 4 + 2 = 6 \\ oc = 8 \div 2 = 4[/tex]

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