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résoudre les équations :

- 12 + 2x = - 5x + 2

4 – (x – 3) = (x – 2) X 3 + 13

2(x – 7) – (3x + 11) = 5 – (2x – 5)


(x – 15) – (4x + 12) = (6 + 2x) – (4 – 5x)

5x – (2x – 11) = (5 – 2x)  3 – (2x + 15)

Bonjour pouvez vous m'aidez avec cet exercice
merci d'avance

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Sagot :

Bonjour,

- 12 + 2x = - 5x + 2

5x+2x  = 2 +12

7x = 14

x = 14/7 = 2

4 – (x – 3) = (x – 2) X 3 + 13

-x +3 = 3x -6 +13

3+6 -13 = 3x +x

-4 = 4x

x=  -4/4 = -1

2(x – 7) – (3x + 11) = 5 – (2x – 5)

2x -14 -3x -11= 5-2x +5

2x-3x+2x  = 5+5 +14 +11

x=  35

(x – 15) – (4x + 12) = (6 + 2x) – (4 – 5x)

x-15 -4x -12 = 6+2x  -4 +5x

-15 -12 -6 +4 = 2x+5x -x +4x

-29 = 10x

x= -29/10 = -2,9

5x – (2x – 11) = (5 – 2x)  3 – (2x + 15)

5x -2x +11= 15 -6x -2x -15

5x+6x+2x = 15 -15 -11

13x = -11

x= -11/13