bonjour
f (x)= 2 - x = affine de forme ax + b
g (x) = - + 1 ??
h (x) = x = linéaire
i (x) = 2 x + 3 x = 5 x donc linéaire
j (x ) = x² - 5 = fonction carrée
k (x) = 6 = constante
l (x) = x² - x = carrée
m (x) = 4 + 7 x - x = 6 x + 4 = affine
n (x) = 5 + 2 x - 6 = 2 x- 1 = affine
p (x) = 4 = constante
9 (x) = v je ne comprends pas