Sagot :
bonjour
f ( 4 ) = 1 et f ( 7) = 2
( 2 - 1 ) / ( 7 - 4 ) = 1 /3
ax = x / 3
f (4) = 1
4 * 1/3 + b = 1
4/3 + b = 1
b = 3/3 - 4/3 = - 1 /3
f (x) = x /3 - 1 /3
f ( 7) = 7 * 1/3 - 1/3 = 7/3 - 1/3 = 6/3 = 2
Réponse :
bonjour,
f(x) = ax + b
on calcule a :
a = (yB - yA)÷(xB - xA )
a = (2 - 1 ) ÷(7 - 4)
a = 1/3
f(x) = 1/3x + b
on calcule b :
f(7) = 2
f(7) = ax + b
1/3 ×7 + b = 2
7/3 + b = 2
b = 2 - 7/3
b = 2/1 - 7/3
b = 6/3 - 7/3
b = -1/3
donc f(x) = 1/3x -1/3
voila:)