1a) A = √98=√2*√49=7√2
B= √242=√2*√121=11√2
C =√245= √5*√49=7√5
D=√605=√5*√121=11√5
b)
E 3√2-2√98+√242/2=
3√2-14√2+(11√2)/2 =
(6√2-28√2+11√2)/2 =-11√2/2
F = 2√605-3√5+√245
F = 22√5-3√5+4√5=23√5
2) [1(√2+1)-1(√2-1)]/(√2+1)(√2-1)=
(√2+1-√2+1)/2-1=
2/-1=-2
H = [1(√5+2)-1(√5-2)]/(√5-2)(√5+2)=
(√5+2-√5+2)/5-4=4/1=4
F =
