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Sagot :

AYUDA

bjr

f(x) = -7x + 3

=> f'(x) = -7

puisque f'(3) = 0

et f'(-7x¹) = -7 * 1 * x¹⁻¹ = -7

Bonjour,

f(x)= 3-7x <=> -7x¹+3

f'(x)= -7(1)= -7

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