Sagot :

Abdobahtar

Réponse:

2(3-x)(2-3x)<0

<=>(6-2x)(2-3x)<0

<=>12-18x-4x+6(x^2)<0

<=>6x^2-22x+12

D=b^2 - 4×a×c

=196

X1=(22+14)÷12

=3

X2=(22-14)÷12

=2/3

S=]-oo;2/3[U]3;+oo[