bonsoir
Comparer les 2 nombres :
Log(0,003) ... log(0,03)
0,003 < 0,03 donc
Log(0,003) < log(0,03)
Log(3 x 10^(-1)) ... log(30 x 10^(-3))
3 x 10^(-1) = 0,3
30 x 10^(-3) = 0,03
3 x 10^(-1) > 30 x 10^(-3) donc
Log(3 x 10^(-1)) > log(30 x 10^(-3)
Log(5/7) ... log(5/11)
5/7 = (5 x 11)/(7 x 11) = 55/77
5/11 = (5 x 7)/(11 x 7) = 35/77
5/7 > 5/11 donc
Log(5/7) > log(5/11)
Log(2) ... log(2/3)
2 = (2 x 3)/3 = 6/3
2 > 2/3 donc
Log(2) > log(2/3)
