Réponse :
je suppose qu'il s'agit des log en base 10
a) log(2x) = log10^3 => 2x = 10³ => x = 500
b) log(x/6) = log10^5 => x/6 = 10^5 => x = 6.10^5
c)?? log5.3^x= log10^10 => log5 + xlog3 = log10^10 => x = (log10^10-log5)/log3
x = 19,49
d) log6^x - log4= lo10^9 => xlog6 = log10^9 + log4
=> x = (log10^9 + log4)/log6 = 12,34
e) log(x+5)= log10^4 => x+5 = 10^4 => x = 10^4 - 5 = 9995
f) log(x+3) - log5 = log10^5 => log(x+3) = log5.10^5 =>x+3 = 5.10^5
=> x = 5.10^5 - 3 = 499997
Bonne journée
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