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Answered

Bonjour est-ce que quelqu’un peut m’aider pour cette exercice

Factoriser en recherchant un facteur commun.
A = (5x – 2) + 4(2x + 1)(5x – 2)
B= (5x - 1)(2x + 3) - 5x + 1
C= 7x(2x + 3) + 2x + 3
D= (7x – 2)(x - 9) + 14x - 4
E= (3x + 5)(x - 1) + (x - 1)
F = (x + 4)2 + (x – 4)(x + 4) + 2x + 8
G= (7x - 2)(3x + 4) - (3x + 4)
H = (2x + 6)(x - 5) + 3x +

Sagot :

MAILYSDAGUERRE
A=(5x-2)+4(2x+1)(5x-2)
=(5x-2)(1+4(2x+1))
=(5x-2)(1+8x+4)
=(5x-2)(5+8x)

B=(5x-1)(2x+3)-5x+1
=(5x-1)(2x+3)-(5x-1)
=(5x-1)(2x+3-1)
=(5x-1)(2x+2)
=(5x-1)*2(x+1)
=2(5x-1)(x+1)

C=7x(2x+3)+2x+3
=7x(2x+3)+(2x+3)
=(2x+3)(7x+1)

D=(7x-2)(x-9)+14x-4
=(7x-2)(x-9)+2(7x-2)
=(7x-2)(x-9+2)
=(7x-2)(x-7)

E=(3x+5)(x-1)+(x-1)
=(x-1)(3x+5+1)
=(x-1)(3x+6)
=(x-1)*3(x+2)
=3(x-1)(x+2)

F=(x+4)2+(x-4)(x+4)+2x+8
=2(x+4)+(x-4)(x+4)+2(x+4)
=(x+4)(2+x-4+2)
=(x+4)(0+x)
=x(x+4)

G=(7x-2)(3x+4)-(3x+4)
=(3x+4)(7x-2-1)
=(3x+4)(7x-3)

H=(2x+6)(x-5)+3x+(-15)
=(2x+6)(x-5)+3x-15
=(2x+6)(x-5)+3(x-5)
=(x-5)(2x+6+3)
=(x-5)(2x+9)

Puisque je n’avais pas la fin du calcul H j’ai pris -15 (vu qu’on peut factoriser avec)

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