Bonjour,
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Exercice 14 :
a. 4x(2x+1) = 0
4x * 2x + 4x * 1 = 0
8x² + 4x = 0
4(2x²+x) = 0
4x(2x+1) = 0
4x = 0 ou 2x + 1 = 0
x = 0 ou x = [tex]\frac{-1}{2}[/tex]
b. (8x+3)² = 0
[tex]\sqrt{(8x+3)^{2} } = \sqrt{0}[/tex]
8x+3 = 0
x = [tex]\frac{-3}{8}[/tex]
c. (x+3) (2x-1) (5-3x) = 0
x+3 = 0 ou 2x-1 = 0 ou 5-3x = 0
x = -3 ou x = [tex]\frac{1}{2}[/tex] ou x = [tex]\frac{3}{5}[/tex]
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Au plaisir d'avoir aidée :)
