Réponse :
bonjour
f (x) = 2 x + 1
f ( 0 ) = 1 ⇔ d 6
f (x) = x/2 + 5
f (2) = 6 ⇔ d 2
f (x) = - 2 x + 5
f ( 1 ) = - 2 + 5 = 3
f ( - 1 ) = 2 + 5 = 7 ⇔ d 4
f ( x) = 5 ⇔ d 3
f (x) = 2 x - 3
f (0) = - 3 ⇔ d 7
f (x) = 2 x - 7
f ( 0 ) = - 7 ⇔ d 8
f (x) = - x /2 + 5
f ( 2 )= - 1 + 5 = 4 ⇔ d 1
f ( x) = 2 x + 5
f ( 1 ) = 7 ⇔ d 5
Explications étape par étape
