A). 2(4x-5)=4+x
8x-10=4+x
8x-x=4+10
7x=14
X=2
B) 2(x+8)+3=4-3x
2x+16+3=4-3x
2x+19=4-3x
2x+3x=4-19
5x=-15
X=-3
C) 12x-1=2(5x-2)+1
12x-1=10x-4+1
12x-1=10x-3
12x-10x=-3+1
2x=-2
X=-1
D) (x-3)2=x(x-5)
2x-6=x**2-5x
2x-6-x**2+5x=0
7x-6-x**2=0
-7x+6+x**2=0
x**2-7x+6=0
x**2-x-6x+6=0
x(x-1)-6(x-1)=0
(x-1)(x-6)=0
x-1=0 ou x-6=0
x=1 ou x=6
Il a tort car il y a 2 solutions pour la D.
