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Sachant que a=9, b= -12, c= 3, calculer
a) a+bc 2) (a+b) xc 3) a+ b sur c

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Bonjour,
a) a+bc=9+(-12)x3=9+(-36)=9-36=-27
b) (a+b)xc=[9+(-12)]x3=-3x3=-9
c) a+b/c=9+(-12)/3=-3/3=-1