Bonjour,
A = [tex]\frac{5n-10}{5} + 2(n+2) = n-2+2n+4=3n+2[/tex]
B = 5(n+4) - 2(n+9) = 5n+20-2n-18=3n+2
C = [tex]\frac{6(n+1)}{2} - 1 = 3(n+1) -1 = 3n + 3 - 2 =3n+2[/tex]
D= 2(2n+1)-n = 4n + 2 - n = 3n+2
E = 7(n-2) - 4(n-4) = 7n-14 - 4n + 16 = 3n+2
F = [tex]\frac{4n+8}{2} + n - 6 = 2n + 4 +n - 6= 3n-2[/tex]
G = [tex]\frac{9n+6}{3} = 3n + 2[/tex]
H = n + 3 +2n -1 = 3n -2
donc c'est la F
