Réponse :
(2x -3)(3x - 1) - (2x - 3)(x -2) = (2x - 3)[3x -1 - (2x -3)]
= (2x - 3)(3x - 1 - 2x +3)
= (2x - 3)(x + 2)
x(3x - 5) + (x +3)(3x - 5) = (3x - 5)[x +(x +3)]
= (3x - 5)(x + x +3)
= (3x -5)(2x +3)
(x -4)² - 7x(x - 4) = (x - 4)(x - 4 -7x)
= (x -4)(-6x - 4)
= 2(x -4)(-3x -2)
j'espère avoir aidé.
