Slt svp aidez-moi j'ai un devoir de math :
Factoriser les expressions suivantes :
A= 16x2 - 9+(4x - 3)(x - 2)
B = (3x + 2)2 - (6x + 4) + 9x² + 12x + 4
C= 100.x2 - 100x + 25 - (6x - 3) (2x + 1)


Sagot :

Réponse:

salut,

A= 16x²-9+(4x-3) (x-2)

A= (4x) ²- 3²+(4x-3) (x-2)

A= (4x+3) (4x-3) +(4x-3) (x-2)

A= (4x-3) [(4x+3) +(x-2) ]

A= (4x-3) [ 4x+3+x-2]

A= ( 4x-3) [ 5x+1]

B= (3x+2) ²-(6x+4) +9x²+12x+4

B= (3x+2) (3x+2) -(6x+4) +(3x) ²+2×3x×2+2²

B= (3x+2) (3x+2) -(6x+4) +(3x+2) ²

B= (3x+2) (3x+2) -(6x+4) + (3x+2) (3x+2)

B= (3x+2) [(3x+2) -(6x+4) ]

B= (3x+2) [ 3x+2-6x-4]

B=(3x+2) [ -3x-2]

C= 100x²-100x+25-(6x-3) (2x+1)

C= (10x) ²-2×10x×5+5²-(6x-3) (2x+1)

C=( 10-5)²-(6x-3) (2x+1)

C= (10x-5) (10x-5) -(6x-3) (2x+1)

C= (10x-5) [ (6x-3) -(2x+1) ]

C= (10x-5) [ 6x-3-2x-1]

C= (10x-5) [4x-4]

voilà