Salut !
1) développons et réduisons (x − 2) (3 − 5x) + (x−2 )²
(x − 2) (3 − 5x) + (x−2 )²
= 3x - 5x² - 6 + 10x + (x² - 4x + 4)
= -5x² + x² + 3x + 10x - 4x - 6 + 4
= -4x² + 9x - 2
2) factorisons (x − 2) (3 − 5x) + (x−2 )²
(x − 2) (3 − 5x) + (x−2 )²
= (x-2)(3-5x) + (x-2)(x-2)
= (x-2)[(3-5x)+(x-2)]
= (x-2)(1-4x)
= (x-2)(-4x+1)
