bjr
[tex]\dfrac{2x+3}{2x+1}=\dfrac{2x+1+2}{2x+1}=1+\dfrac{2}{2x+1} \\\\\ln (\dfrac{2x+3}{2x+1})= \ln(1+\dfrac{2}{2x+1} ) \text{ equivalent a } \dfrac{2}{2x+1}\\\\(\dfrac{2x+3}{2x+1})^{x+1}=exp((x+1)\ln(1+\dfrac{2}{2x+1} ) )\rightarrow exp(1)=e[/tex]
Merci
