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NADIA0R
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Factorise les expressions suivantes :
A = (x+3) (x + 5)-3 (x + 5):
B = (2x + 3) (x - 4) + (3 x – 5) (x – 4)
C = (3 x - 1) (x - 2) - (2 x + 5) (3x - 1)
D = x (2 x + 3) - 7 (2 x + 3)
svp aidez-moi merci ! ​

Sagot :

HIBBAMAHROUK

Réponse:

A=x(x+5)

B=(x-4)(5x-2)

C= (3x-1)(-x-7)

D=(2x+3)(x-7)

Explications étape par étape:

  1. (x+3)(x+5)-3(x+5)=

(x+5)(x+3-3)

(x+5)(×)

x(x+5)

(2x+3)(x-4)+(3x-5)(x-4)

(x-4)(2x+3+3x-5)

(x-4)(5x-2)

C=(3x-1)(x-2-2x-5)

(3x-1)(-x-7)

D=x(2x+3)-7(2x+3)

(2x+3)(x-7)

Salut

[tex]\rule{7cm}{1mm}[/tex]

A = (x + 3) (x + 5) -3 (x + 5)

A = (x + 5)[(x + 3) - 3]

A = (x + 5)(x + 3 - 3)

A = (x + 5)(x)

B = (2x + 3) (x - 4) + (3x - 5) (x - 4)

B = (x - 4)[(2x + 3) + (3x - 5)]

B = (x - 4)(2x + 3 + 3x - 5)

B = (x - 4)(5x - 2)

C = (3x - 1) (x - 2) - (2x + 5) (3x - 1)

C = (3x - 1)[(x - 2) - (2x + 5)]

C = (3x - 1)(x - 2 - 2x - 5)

C = (3x - 1)(-x - 7)

D = x(2x + 3) - 7(2x + 3)

D = (2x + 3)(x - 7)

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