Answered

Salut svp il faut développer et reduire :
A = (3x – 5)² + (2x + 5)²
B = 7x (3x – 4) – (x – 3)²


et la il faut résoudre les equations

c) -2(x + 4) + 12 = 5x – (7x – 4)
d) (x + 1) (-x + 4) – (x + 1)(5x – 3)=0
e) 25x² – 4=0


Merci

Sagot :

A=(3x-5)(3x-5)+(2x+5)(2x+5)

=(9x-15x-15x+25)(4x+10x+10x+25)+131

=9x-15x-15x+25+4x+10x+10x+25

=-15x-15x+4x+10x+10x+9x+25+25

=-20x+33x+50

A =+13x+50