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a bullet of mass 6g travelling at 126m/s^2 penetrates into a fixed target and is brought to rest in 0.01s.determine(a)the distance of penetration in the target (b) average regarding force exerted on a bullet​

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ARIANASARAH

Hello

First thing we have to find a

a = v-u/0.01 = 126-0/0.01=12600m /s^2

And now s = u^2/2a = 126*126/2*12600=0.63m

F = ma = 0.006*12600=75.6N