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Sagot :

Bonjour

Soit f : x + 2x + 3

a. Calculer

f(0) =  f (0) = 0 + 2 * 0 + 3 = 3

f(5) =  f (5) = 5 + 2 * 5 + 3 = 5 + 10 + 3 = 18

f(12) =  f (12) = 12 + 2 * 12 + 3 = 12 + 24 + 3 = 39

b. Calculer les antécédents de 7 et de 41.​

x + 2x + 3 = 7

3x = 7 - 3

3x = 4

x = 4/3

x + 2x + 3 = 41

3x = 41 - 3

3x = 38

x = 38/3.

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